a)
here question is not given ; I think it is probabiliy of a person to have height less than 72 ' please revert:
for normal distribution z score =(X-μ)/σ | |
here mean= μ= | 69 |
std deviation =σ= | 2.800 |
hence P( having height less than 72):
probability = | P(X<72) | = | P(Z<1.07)= | 0.8577 |
b)
sample size =n= | 200 |
std error=σx̅=σ/√n= | 0.1980 |
probability = | P(X<72) | = | P(Z<15.15)= | 1.0000 |
c)
here part a is more important as we need to check for an individual person comfort ; not the average of these people,
d)
as it is assumed that mean height of women might be less than men; therefore if it is comfortable and safe for male ; it should be comfortable and safe for female.
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