The life of a certain AAA batteries is normally distributed with a variance of 100 hours and mean of 550 hours. Find the probability that a battery chosen at random will last no more than 568 hours
Solution :
Given that ,
mean =
= 550
standard deviation =
=
variance
=
100
= 10
P(x 568)
= P[(x -
) /
(568 -550) /10 ]
= P(z
1.8 )
= 0.9641
probability =0.9641
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