The life of a certain AAA batteries is normally distributed with a variance of 100 hours and mean of 550 hours. Find the probability that a battery chosen at random will last no more than 568 hours
Solution :
Given that ,
mean = = 550
standard deviation = = variance =100 = 10
P(x 568)
= P[(x - ) / (568 -550) /10 ]
= P(z 1.8 )
= 0.9641
probability =0.9641
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