Question

The life of a certain AAA batteries is normally distributed with a variance of 100 hours and mean of 550 hours. Find the probability that a battery chosen at random will last no more than 568 hours

Answer #1

Solution :

Given that ,

mean = = 550

standard deviation = = variance =100 = 10

P(x 568)

= P[(x - ) / (568 -550) /10 ]

= P(z 1.8 )

= 0.9641

probability =0.9641

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