Question

0

0

0

0

0

0

0

0

0

0

0

0

67

82

83

95

100

149

159

181

188

203

244

262

281

289

300

310

316

331

347

367

375

389

403

454

476

479

521

527

547

567

579

628

635

650

671

719

736

1277

Find the 5 number summary of the data set shows. Identify any outliers.

Answer 1

s. no	X
1	0
2	0
3	0
4	0
5	0
6	0
7	0
8	0
9	0
10	0
11	0
12	0
13	67
14	82
15	83
16	95
17	100
18	149
19	159
20	181
21	188
22	203
23	244
24	262
25	281
26	289
27	300
28	310
29	316
30	331
31	347
32	367
33	375
34	389
35	403
36	454
37	476
38	479
39	521
40	527
41	547
42	567
43	579
44	628
45	635
46	650
47	671
48	719
49	736
50	1277

from above minimum number =0

quartile 1=(n+1)/4 th value =(50+1)/4 th value =12.75 th value =0+.75*(67-0)=50.25

median =(n+1)./2 th value =25.5 th value =281+0.5*(289-281)= 285

quartile 3=3*(n+1)/4 th value =3*(50+1)/4 th value =38.25 th value =479+0.25*(521-479)=489.5

maximum value =1277

theefore 5 number summary =0 ; 50.25 ;285 ; 489.5 ;1277

here lower fence =Q1-1.5*(Q3-Q1)=50.25-1.5*(489.5-50.25)=-608.625

and upper fence =Q3+1.5*(Q3-Q1)=489.5+1.5*(489.5-50.25)=1148.375

therefore outlier is 1277