Question

Listed below are the amounts of mercury​ (in parts per​ million, or​ ppm) found in tuna sushi sampled at different stores. The sample mean is

1.004ppm and the sample standard deviation is 0.367 ppm. Use technology to construct a 90​% confidence interval estimate of the mean amount of mercury in the population.

0.96

0.57

1.43

1.38

0.53

1.25

0.91

What is the confidence interval estimate of the mean amount of mercury in the​ population?

​(Round to three decimal places as​ needed.)

Answer 1

Solution :

We have,

= 7.03 / 7 = 1.004

s = 0.367

t _/2,df = 1.943

Margin of error = E = t_/2,df * (s /n)

= 1.943 * (0.367 / 7)

Margin of error = E = 0.270

The 90% confidence interval estimate of the population mean is,

- E < < + E

1.004 - 0.270 < < 1.004 + 0.270

0.734 < < 1.274

(0.734 , 1.274)