(1 point)
Type I error is:
A. Deciding the null hypothesis is true when it is
false
B. Deciding the alternative hypothesis is true
when it is false
C. Deciding the null hypothesis is false when it
is true
D. Deciding the alternative hypothesis is true
when it is true
E. All of the above
F. None of the above
Type II error is:
A. Deciding the null hypothesis is false when
it is true
B. Deciding the alternative hypothesis is true
when it is true
C. Deciding the alternative hypothesis is false
when it is true
D. Deciding the null hypothesis is true when it is
false
E. All of the above
F. None of the above
Select True or False from each pull-down menu, depending on whether the corresponding statement is true or false.
? True False 1. A two-tail test is a test in which a null hypothesis can be rejected by an extreme result occurring in only one direction.
? True False 2. The probability of a Type I error is represented by ββ, and is the probability of failing to reject a false null hypothesis.
? True False 3. A one-tail pp-value is twice the size of a two-tail test.
? True False 4. The power of a test is the probability that a true null hypothesis will be rejected.
(2 points) The hypothesis test
H0:μ=33H1:μ≠33H0:μ=33H1:μ≠33
is to be carried out. A random sample is selected, and yields
x¯=36x¯=36 and s = 5. If the value of the t statistic is
t=3.49857113690718t=3.49857113690718, what is the sample size? (If
rounding is required, round to the nearest integer.)
Sample Size
Ans:
1)Type I error is:
Deciding the null hypothesis is false when it is true.
2)Type II error is:
Deciding the null hypothesis is true when it is false.
3)
A two-tail test is a test in which a null hypothesis can be rejected by an extreme result occurring in only one direction.(False)
The probability of a Type I error is represented by β, and is the probability of failing to reject a false null hypothesis.(False)
A one-tail p-value is twice the size of a two-tail test.(False)
The power of a test is the probability that a true null hypothesis will be rejected.(False)
4)
t=3.49857=(36-33)/(5/sqrt(n))
3.49857=3/(5/sqrt(n))
3.49857=0.6*sqrt(n)
sqrt(n)=3.49857/0.6=5.83
n=34
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