Question

test the hypothesis that Florida has been the dominant orange-producing state in the US historically (e.g....

test the hypothesis that Florida has been the dominant orange-producing state in the US historically (e.g. conduct an upper tailed test for Florida compared to the total US values excluding Florida (column F)). Assume a z-distribution

Year FLORIDA Non-Florida
1970 137.7 48.07
1971 142.3 47.13
1972 137 54.45
1973 169.7 54.96
1974 165.8 50.41
1975 173.3 64.51
1976 181.2 61.58
1977 186.8 56.15
1978 167.8 52.32
1979 164 46.6
1980 206.7 66.93
1981 172.4 72.18
1982 125.8 50.89
1983 139.6 85.58
1984 116.7 52.74
1985 103.9 54.45
1986 119.2 56.24
1987 119.7 61.475
1988 138 62.25
1989 146.6 62.45
1990 110.2 74.215
1991 151.6 27.35
1992 139.8 69.81
1993 186.6 69.16
1994 174.4 66.05
1995 205.5 58.105
1996 203.3 60.59
1997 226.2 66.82
1998 244 71.525
1999 186 38.58
2000 233 66.76
2001 223.3 57.635
2002 230 53.76
2003 203 64.04
2004 242 52.62
2005 149.8 66.7
2006 147.7 63.05
2007 129 48.28
2008 170.2 64.176
2009 162.5 48.209
2010 133.7 59.135
2011 140.5 64.449
2012 146.7 59.419
2013 133.6 56.293
2014 104.7 51.277
2015 96.95 49.652
Grand Total 7488.45 2689.025

Homework Answers

Answer #1

Data:     

n1 = 46    

n2 = 46    

x1-bar = 162.79    

x2-bar = 58.46    

s1 = 39    

s2 = 10    

Hypotheses:    

Ho: μ1 ≤ μ2    

Ha: μ1 > μ2    

Decision Rule:    

α = 0.05    

Critical z- score = 1.64485363   

Reject Ho if z > 1.64485363   

Test Statistic:    

SE = √{(s1^2 /n1) + (s2^2 /n2)} = √((39)^2/46) + ((10)^2/46)) = 5.9363

z = (x1-bar - x2-bar)/SE = (162.79 - 58.46)/5.93625559041915 = 17.575

p- value = 0    

Decision (in terms of the hypotheses):

Since 17.57505 > 1.644853627 we reject Ho and accept Ha

Conclusion (in terms of the problem):

There is sufficient evidence that Florida has been the dominant orange-producing state in the US.

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