Question

The grade point averages (GPA) for 12 randomly selected college students are shown on the right. Complete parts (a) through (c) below. Assume the population is normally distributed.

2.3 3.4 2.8 1.8 0.9 4.0 2.5 1.1 3.8 0.5 2.2 3.2

(a) Find the sample mean. x overbarequals =

(Round to two decimal places as needed.)

(b) Find the sample standard deviation. sequals =

(Round to two decimal places as needed.)

(c) Construct a 95% confidence interval for the population mean mu.

A 95% confidence interval for the population mean is left parenthesis = comma right parenthesis .=

(Round to two decimal places as needed.)

Answer #1

the necessary calculation table is :-

GPA(x) |
x^{2} |

2.3 | 5.29 |

3.4 | 11.56 |

2.8 | 7.84 |

1.8 | 3.24 |

0.9 | 0.81 |

4 | 16 |

2.5 | 6.25 |

1.1 | 1.21 |

3.8 | 14.44 |

0.5 | 0.25 |

2.2 | 4.84 |

3.2 | 10.24 |

sum=28.5 |
sum=81.97 |

sample size(n) = 12

a).**the sample
mean is:-**

b). **the sample
standard deviation is:-**

c).degrees of freedom =(n-1)=(12-1)=11

*t critical value
for df=11,alpha=0.05, both tailed test be:-*

[ using t distribution table ]

**A 95%
confidence interval for the population mean
is:-**

*** if you have any doubt regarding the problem please write it
in the comment box.if you are satisfied please give me a
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