Question

Find the percent of observations from a standard normal distribution that satisfies each of the following statements. Note: Enter your answers as a percentage.

z>1.43:  %

z<1.43:  %

z>−1.09:  %

−1.09<z<1.43:

Answer 1

Solution:

Given that,

a ) P( z > 1.43 )

1 - P ( z < 1.43 )

Using standard normal table

= 1 - 0.9236

= 0.0764

Probability = 07.64%

b ) P ( z < 1.43 )

Using standard normal table

= 0.9236

Probability = 92.36%

c ) P( z > -1.09 )

1 - P ( z < -1.09 )

Using standard normal table

= 1 - 0.1379

= 0.8621

Probability = 86.21%

d ) P ( -1.09 < z < 1.43 )

= P ( z 1.43 ) - P ( z < - 1.09 )

Using standard normal table

= 0.9236 -0.1379

=0.7857

Probabilty = 78.57%