Question

Use the given data to find the sample size required to estimate the population proportion. Margin of error: 0.012; confidence level: 98%; p and q unknown

Answer 1

Solution :

Given that,

= 0.5

1 - = 0.5

margin of error = E = 0.012

At 98% confidence level the z is ,

= 1 - 98% = 1 - 0.98 = 0.02

/ 2 = 0.02 / 2 = 0.01

Z_/2 = Z_0.01 = 2.326

sample size = n = (Z _{/ 2} / E )² * * (1 - )

= (2.326 / 0.012)² * 0.5*0.5

= 9392.84

sample size = 9393