Question

Use the given data to find the sample size required to estimate the population proportion. Margin of error: 0.012; confidence level: 98%; p and q unknown

Answer #1

Solution :

Given that,

= 0.5

1 - = 0.5

margin of error = E = 0.012

At 98% confidence level the z is ,

= 1 - 98% = 1 - 0.98 = 0.02

/ 2 = 0.02 / 2 = 0.01

Z_{/2}
= Z_{0.01} = 2.326

sample size = n = (Z_{
/ 2} / E )^{2} *
* (1 -
)

= (2.326 / 0.012)^{2} * 0.5*0.5

= 9392.84

**sample size = 9393**

Use the given data to find the minimum sample size required to
estimate the population proportion.
Margin of error: 0.008; confidence level: 98%;
ModifyingAbove p with caret
and
ModifyingAbove q with caret
unknown

Use the given data to find the minimum sample size required to
estimate the population proportion. Margin of error: 0.008;
confidence level: 98%; ModifyingAbove p with caret and
ModifyingAbove q with caret unknown A. 22,184 B. 10,384 C.
20,308 D. 21,207

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Show All Work
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unknown.
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