Question

A student was asked to find a 98% confidence interval for widget width using data from a random sample of size n = 25. Which of the following is a correct interpretation of the interval 14.2 < μ < 24.4?

Check all that are correct.

- There is a 98% chance that the mean of a sample of 25 widgets will be between 14.2 and 24.4.
- With 98% confidence, the mean width of all widgets is between 14.2 and 24.4.
- The mean width of all widgets is between 14.2 and 24.4, 98% of the time. We know this is true because the mean of our sample is between 14.2 and 24.4.
- There is a 98% chance that the mean of the population is between 14.2 and 24.4.
- With 98% confidence, the mean width of a randomly selected widget will be between 14.2 and 24.4.

Answer #1

A student was asked to find a 98% confidence interval for the
population proportion of students who take notes using data from a
random sample of size n = 84. Which of the following is a correct
interpretation of the interval 0.1 < p < 0.33?
Check all that are correct.
____With 98% confidence, the proportion of all students who
take notes is between 0.1 and 0.33.
____The proprtion of all students who take notes is between 0.1
and 0.33,...

A student was asked to find a 90% confidence interval for the
proportion of students who take notes using data from a random
sample of size n = 88. Which of the following is a correct
interpretation of the interval 0.1 < p < 0.3?
Check all that are correct.
The proprtion of all students who take notes is between 0.1 and
0.3, 90% of the time.
There is a 90% chance that the proportion of notetakers in a
sample...

A student was asked to find a 90% confidence interval for the
proportion of students who take notes using data from a random
sample of size n = 84. Which of the following is a correct
interpretation of the interval 0.1 < p < 0.31? Check all that
are correct. With 90% confidence, a randomly selected student takes
notes in a proportion of their classes that is between 0.1 and
0.31. There is a 90% chance that the proportion of...

A student was asked to find a 90% confidence interval for the
proportion of students who take notes using data from a random
sample of size n = 78. Which of the following is a correct
interpretation of the interval 0.13 < p < 0.27?
Check all that are correct.
0 There is a 90% chance that the proportion of the population is
between 0.13 and 0.27.
0 The proprtion of all students who take notes is between 0.13
and...

The width of a confidence interval will be:
Narrower for 98 percent confidence than for 90 percent
confidence.
Wider for a sample size of 64 than for a sample size of 36.
Wider for a 99 percent confidence than for 95 percent
confidence.
Narrower for a sample size of 25 than for a sample size of
36.
None of these.

Based on a simple random sample of size 90, an 84% confidence
interval for the unknown mean SAT MATH score, μμ, in some large
population is 517<μ<525517<μ<525.
Which of the following is/are correct interpretation(s) of this
confidence interval?There may be more than one correct answer; you
must check all correct answers in order to get credit for this
problem.
A. 84% of individuals in this sample have a mean
SAT MATH score between 517 and 525.
B. 84% of individuals...

Suppose we construct a 98% confidence interval for the mean. The
interval ranges from [1100, 1200]. The 98% confidence interval for
the population mean can be interpreted as follows:
If all possible samples are taken and confidence intervals are
calculated, 98% of those intervals would include the true
population mean somewhere in their interval.
One can be 98% confident that you have selected a sample whose
range does not include the population mean.
One can be 98% confident that the...

Use the sample data to find a 99% confidence interval for the
average monthly student loan payment among all recent college
graduates who had at least one student loan during college.Round
all answers to the nearest cent (two decimal places).The margin of
error for this confidence interval is: $
The 99% confidence interval is:$
<μ<<μ< $
The heights of all women in a large population follow a Normal
distribution with unknown mean μμ. In a simple random sample of 44...

The 98% confidence interval for the mean, calculated from a
sample is 1.275775≤μ≤2.524225. Determine the sample mean =
. Assuming that the data is normally distributed with the
population standard deviation =1.2, determine the size of the
sample n=

Use the given degree of confidence and sample data to construct
a confidence interval for the population mean μ. Assume that the
population has a normal distribution. Thirty randomly selected
students took the calculus final. If the sample mean was 95 and the
standard deviation was 6.6, construct a 99% confidence interval
for the mean score of all students.
A.92.95 <μ <97.05
B.92.03 <μ <97.97
C.91.69 <μ <98.31
D.91.68 <μ <98.32

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