Question

The response is the tooth length in n = 60 guinea pigs. Each animal received a...

The response is the tooth length in n = 60 guinea pigs. Each animal received a daily dose of vitamin C by one of two delivery methods (orange juice or ascorbic acid). The estimated mean function is E(length|source, dose) = 11.5 + 8.5 source + 8.0 dose + 4.0 source × dose where source takes the value 1 for ascorbic acid and 0 for orange juice.
Suppose the variable source was re-coded to take the value 1 for orange juice and 0 for ascorbic acid. Then the estimated mean function becomes what? Please include explaination.

Homework Answers

Answer #1

E(length|source, dose) = 11.5 + 8.5 source + 8.0 dose + 4.0 source × dose

for ascorbic acid , source = 1

hence for ascorbic acid

E(length|source, dose) = 11.5 + 8.5 + 8.0 dose + 4.0 dose

= 20 + 12 dose

for orange juice

E(length|source, dose) = 11.5 + 8.0 dose

hence if we code source = 1 for orange juice

E(length|source, dose) = a + b source + c dose + d source × dose

for orange juice = a + b + (c+ d) dose

for ascorbic acid = a+ c dose

hence

a+b = 11.5 , c+d = 8 , a = 20 ,c = 12

b - -8.5 , d = -4

E(length|source, dose) = 20 -8.5 source + 12 dose -4 source × dose

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT