normal distribution. When a sample of twenty-nine cells were observed, the mean
time taken by them to divide into two was 31.1 minutes with a standard deviation
of 3.7 minutes. At α = .01, test the claim that the true mean time is 30 minutes.
Given that, sample size (n) = 29, sample mean = 31.1 minutes and sample standard deviation (s) = 3.7 minutes
The null and alternative hypotheses are,
H0 : μ = 30 minutes
Ha : μ ≠ 30 minutes
This hypothesis test is a two-tailed test.
Test statistic is,
=> Test statistic = t = 1.601
Degrees of freedom = 29 - 1 = 28
Using Excel we find the p-value as follows :
Excel Command : =TDIST (1.601, 28, 2) = 0.1206
=> p-value = 0.1206
Since, p-value is greater than 0.01 significance level, we fail to reject the null hypothesis (H0).
Conclusion : There is not sufficient evidence to warrant rejection of the claim that the true mean time is 30 minutes.
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