Question

5. A sample of 120 body builders have an average weight of of 278.20 pounds and...

5. A sample of 120 body builders have an average weight of of 278.20 pounds and a sample standard deviation of 12.62 pounds. Construct a 99% confidence interval estimate the mean of the weight of bodybuilders for the entire population.

a) Find the margin of error, E

b) What is the Confidence Interval?

c) Interpret the confidence interval.

Math   Statistics-And-Probability   
0 0
Add a commentTranscribed image text
Next >

Homework Answers

Answer #1

Sample mean, = 278.20 pounds

Standard deviation, = 12.62 pounds

Sample size, n = 120

Corresponding to 99% confidence interval, the z score = 2.575

(a) Margin of error, E = = 2.967

(b) The confidence Interval is ()

= (275.233, 281.167) pounds

(c) With 99% confidence, the population mean weight of bodybuilders is between 275.233 pounds and 281.167 pounds, based on 120 samples

0 0
Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A sample of 120 body builders have an average of 278.20 pounds and a sample standard...
A sample of 120 body builders have an average of 278.20 pounds and a sample standard deviation of 12.62 pounds. Construct a 95% confidence interval to estimate the population standard deviation of the weights of body builders
The trout in a lake have historically had an average weight of 11.2 pounds. It is...
The trout in a lake have historically had an average weight of 11.2 pounds. It is suspected that pollution from a nearby factory has affected the weight of trout in recent years. Suppose you take a random sample of 50 trout from the lake, and you find that the sample mean of their weight is 10.2 pounds, with a sample standard deviation of 2.1 pounds. (a) The standard error of the (sample) mean is ­­­­­___________________________ (b) Find a 95% confidence...
5. How heavy are the backpacks carried by college students? To estimate the weight of backpacks...
5. How heavy are the backpacks carried by college students? To estimate the weight of backpacks carried by college students, a researcher weighs the backpacks from a random sample of 58 college students. The average backpack weight ends up being 15.7 pounds, with a standard deviation of 2.4 pounds. If you use this data to construct a 90% confidence interval, what will the margin of error be for this interval? Try not to do a lot of intermediate rounding until...
A medical statistician wants to estimate the average weight loss of those who have been on...
A medical statistician wants to estimate the average weight loss of those who have been on a new diet plan for 2 weeks. From a random sample of 100 participants in the diet plan, a mean weight change of -2.5 pounds and a standard deviation of 10 pounds are observed. In order to claim that the diet plan is effective, the whole part of the confidence interval for the mean weight change has to be below zero. In other words,...
A sample of 7 adult elephants has an average weight of 12,800 pounds. the standard deviation...
A sample of 7 adult elephants has an average weight of 12,800 pounds. the standard deviation for the sample was 21 pounds.find the 99% confidence interval of the population mean for the weight of adult elephants.assume the value is normally distributed. use a graphing calculator and round up answer to the nearest whole number.
assume that in a particular region, wild salmon have an average weight of 5 pounds with...
assume that in a particular region, wild salmon have an average weight of 5 pounds with a standard deviation of 1.6 pounds. a. Find the probability that a salmon's weight is between 4.1 pounds and 5.5 pounds. b. Find P80, the 80th percentile of salmon weights. c. Assume that a sample of 25 salmon is randomly taken from the preceding population and the mean of their weights recorded. Give the mean μx and the standard deviation σx of the sample...
A sample of 15 small bags of Skittles was selected. The mean weight of the sample...
A sample of 15 small bags of Skittles was selected. The mean weight of the sample of bags was 2 ounces and the standard deviation was 0.12 ounces. The population standard deviation is known to be 0.1 ounces. (Assume the population distribution of bag weights is normal) a) Construct a 95% confidence interval estimating the true mean weight of the candy bags. (4 decimal places b) What is the margin of error for this confidence interval? c) Interpret your confidence...
You measure 33 watermelons' weights, and find they have a mean weight of 61 ounces. Assume...
You measure 33 watermelons' weights, and find they have a mean weight of 61 ounces. Assume the population standard deviation is 14.9 ounces. Based on this, construct a 99% confidence interval for the true population mean watermelon weight. Round your answers to two decimal places. Enter your answers in the form: Sample Mean ± Margin of Error  
The standard deviation of the weights of elephants is known to be approximately 15 pounds. We...
The standard deviation of the weights of elephants is known to be approximately 15 pounds. We wish to construct a 95% confidence interval for the mean weight of newborn elephant calves. Fifty newborn elephants are weighed. The sample mean is 244 pounds. The sample standard deviation is 11 pounds. Identify the following: x¯ = σ = n = In words, define the random variables X and X¯. Construct a 95% confidence interval for the population mean weight of newborn elephants....
1) You measure 25 textbook' weights, and find they have a mean weight of 60 ounces....
1) You measure 25 textbook' weights, and find they have a mean weight of 60 ounces. Assume the population standard deviation is 9.2 ounces. Based on this, what is the maximal margin of error associated with a 90% confidence interval for the true population mean backpack weight. Give your answer as a decimal, to two places a) You measure 46 textbooks' weights, and find they have a mean weight of 48 ounces. Assume the population standard deviation is 7.8 ounces....
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT