Question

We want to compare the weights of two independent groups of mice. Group 1 consists of 14 mice that were fed only cheese. Group 2 consists of 15 dogs that were fed only walnuts. Group 1 information: sample mean x1-bar = 18 and sample standard deviation s1 = 4. Group 2 information: sample mean x2-bar = 18 and sample standard deviation s2 = 7. Perform a 2-sided hypothesis test of H0: mu1 = mu2 against H1: mu1 not equal to mu2. Do not assume the two samples share the same variance. Find the P-value. Answer to three decimal places.

Answer 1

here p-value=1.000

here we use t-test with

null hypothesis H0:mean1=mean2 and alternate hypothesis H1:mean1≠mean2

statistic t=(mean1-mean2)/((sqrt(s1²/n1+s2²/n2)) =0/sqrt(4.4095)=0/2.0739=0

with df ==

	sample	mean	s	s2	n	s2/n	(s2/n)2)/(n-1)
	Group1	18.0000	4.0000	16.0000	14	1.1429	0.100
	Group2	18.0000	7.0000	49.0000	15	3.2667	0.762
	difference=	0.0000	sum=	65.0000	29	4.409524	0.86269318
	df=	22.5386
	SE=	2.0999
	t=	0.0000
two tailed	p-value=	1.0000
critical	t(0.05)	2.0739