Mean = 120
Sd = 20
a)
He will pass the if the P[ X > mean + 20 ] = P[ X > 120+20 ] = P[ X > 140 ] > 10%
P[ X > 140 ] = P[ ( X - mean )/sd > ( 140 - mean )/sd ] = P[ ( X - 120 )/20 > ( 140 - 120 )/20 ] = P[ Z > 1 ] = 0.1587
Since it is more than 10% (0.1 )
hence, he will not clear
b)
Cut off will be x if
P[ X > x ] = 90% = 0.9
P[ X > x ] = P[ ( X - mean )/sd > ( x - mean )/sd ] = P[ ( X - 120 )/20 > ( x - 120 )/20 ] = P[ Z > ( x - 120 )/20 ] = 0.9
We know that P[ Z > 1.28 ] = 0.9
( x - 120 )/20 = 1.28
x - 120 = 1.28*20
x - 120 = 25.6
x = 120 + 25.6
x = 145.6
cut off = 145.6
The corresponding Z score is 1.28
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