A statistics teacher claims that, on average, 20% of her students get a grade of A, 35% get a B, 25% get a C, 10% get a D, and 10% get an F. The grades of a random sample of 100 are shown below. Use a = 0.05 to test the claim that the grades follow the distribution claimed by the teacher.
Grade # of Students
A 29
B 42
C 20
D 5
F 4
null hypothesis: Ho:grades follow the distribution claimed by the teacher.
alternate hypothesis:Ha: Not all grades follows the distribution claimed by the teacher.
degree of freedom =categories-1=5-1=4
for 4 df and 0.05 level rejection region >9.488
applying chi square goodness of fit :
observed | Expected | Chi square | |||
category | Probability(p) | Oi | Ei=total*p | R2i=(Oi-Ei)2/Ei | |
A | 0.200 | 29.000 | 20.000 | 4.050 | |
B | 0.350 | 42.000 | 35.000 | 1.400 | |
C | 0.250 | 20.000 | 25.000 | 1.000 | |
D | 0.100 | 5.000 | 10.000 | 2.500 | |
E | 0.100 | 4.000 | 10.000 | 3.600 | |
total | 1.000 | 100 | 100 | 12.550 |
as test statistic 12.550 is in critical region we reject null hypothesis
we have sufficient evidence at 0.05 level to reject the claim that the grades follow the distribution claimed by the teacher.
Get Answers For Free
Most questions answered within 1 hours.