Question

According to a survey by the U.S. Bureau of Labor statistics, 87% of all the part-time college students also work. If this figure still holds and if 100 part-time college students are randomly selected, what is the probabilities that less than 70 part-time college students also work?

Answer #1

Solution :

Given that,

p = 0.87

q = 1 - p = 1 - 0.87 = 0.13

n = 100

Using binomial distribution,

= n * p = 100 * 0.87 = 87

= n * p * q = 100 * 0.87 * 0.13 = 3.3630

Using continuity correction ,

P(x < 70 - 0.5) = P(x < 69.5

= P((x - ) / < (69.5 - 87) / 3.3630)

= P(z < -5.20)

= 0

the probabilities that less than 70 part-time college students also work is 0 .

According to the U.S. Bureau of Labor Statistics, the response
rate to the 2017 Consumer Expenditure Quarterly Survey (CEQ) was
60.9 percent. Let’s assume this figure will hold true for 2020 as
well. Given the fact and the assumption, what is a close
approximation to the probability that at least 7,000 out of 11,000
households contacted will respond to the 2020 CEQ?
(a) 0.454
(b) 0.115
(c) 0

According to the U.S. Bureau of Labor Statistics, the average
weekly earnings of a production worker in manufacturing in the
United States as of October 2014 was $827.27. Suppose a labor
researcher wants to test to determine whether this figure is still
accurate today. The researcher randomly selects 54 production
workers from across the United States and obtains a representative
earnings statement for one week from each worker. The resulting
sample average is $843.56. Assuming a population standard deviation
of...

According to the U.S. Bureau of Labor Statistics, the average
weekly earnings of a production worker in July 2011 were $657.49.
Suppose a labor researcher wants to test to determine whether this
figure is still accurate today. The researcher randomly selects 53
production workers from across the United States and obtains a
representative earnings statement for one week from each. The
resulting sample average is $670.16. Assuming a population standard
deviation of $63.90 and a 10% level of significance, determine...

According to the U.S. Bureau of Labor Statistics, the average
weekly earnings of a production worker in July 2011 were $657.49.
Suppose a labor researcher wants to test to determine whether this
figure is still accurate today. The researcher randomly selects 53
production workers from across the United States and obtains a
representative earnings statement for one week from each. The
resulting sample average is $672.65. Assuming a population standard
deviation of $63.90 and a 1% level of significance, determine...

According to the U.S. Bureau of Labor Statistics, the average
weekly earnings of a production worker in July 2011 were $657.49.
Suppose a labor researcher wants to test to determine whether this
figure is still accurate today. The researcher randomly selects 54
production workers from across the United States and obtains a
representative earnings statement for one week from each. The
resulting sample average is $672.41. Assuming a population standard
deviation of $63.90 and a 5% level of significance, determine...

According to the U.S. Bureau of Labor Statistics, the average
weekly earnings of a production worker in July 2011 were $657.49.
Suppose a labor researcher wants to test to determine whether this
figure is still accurate today. The researcher randomly selects 53
production workers from across the United States and obtains a
representative earnings statement for one week from each. The
resulting sample average is $672.44. Assuming a population standard
deviation of $63.90 and a 5% level of significance, determine...

According to the U.S. Bureau of Labor Statistics, the average
weekly earnings of a production worker in July 2011 were $657.49.
Suppose a labor researcher wants to test to determine whether this
figure is still accurate today. The researcher randomly selects 53
production workers from across the United States and obtains a
representative earnings statement for one week from each. The
resulting sample average is $672.15. Assuming a population standard
deviation of $63.90 and a 1% level of significance, determine...

According to the U.S. Bureau of Labor Statistics, the average
weekly earnings of a production worker in July 2011 were $657.49.
Suppose a labor researcher wants to test to determine whether this
figure is still accurate today. The researcher randomly selects 55
production workers from across the United States and obtains a
representative earnings statement for one week from each. The
resulting sample average is $672.84. Assuming a population standard
deviation of $63.90 and a 5% level of significance, determine...

According to the Bureau of Labor Statistics, 7.1% of the labor
force was recently unemployed. A random sample of 100 employable
adults was selected.
Using the normal distribution, approximate the probability that
10 or less people from this sample are unemployed.
Using the normal distribution, approximate the probability that
6 or more people from this sample are unemployed.

The U.S. Bureau of Labor Statistics released hourly wage figures
for various countries for workers in the manufacturing sector. The
hourly wage was $30.67 for Switzerland, $20.20 for Japan, and
$23.82 for the U.S. Assume that in all three countries, the
standard deviation of hourly labor rates is $3.00.
a. Suppose 42 manufacturing workers are selected
randomly from across Switzerland and asked what their hourly wage
is. What is the probability that the sample average will be between
$30.00 and...

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 6 minutes ago

asked 18 minutes ago

asked 34 minutes ago

asked 42 minutes ago

asked 42 minutes ago

asked 44 minutes ago

asked 57 minutes ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago