The data for comparing two sample proportions can be presented in a two-way table containing the counts of successes and failures in both samples, with two rows and two columns. In Exercise 23.2, a survey of the consequences of video-gaming on 14- to 18-year-olds is described. Another question from the survey was about aggressive behavior as evidenced by getting into serious fights, and the comparison was between girls that have and have not played video games. Here are the data:
Serious Fights-Yes | Serious Fights-No | |
Played games | 36 | 55 |
Never played games | 578 | 1436 |
Is there evidence that the proportions of 14- to 18-year-old girls who have or have not gotten into serious fights differ between those who have played or never have played video games? Find the chi-square statistic x2 and its P-value.
Ans:
Observed(fo) | |||
Yes | No | Total | |
Played games | 36 | 55 | 91 |
Never played games | 578 | 1436 | 2014 |
Total | 614 | 1491 | 2105 |
Expected(fe) | |||
Yes | No | Total | |
Played games | 26.54 | 64.46 | 91 |
Never played games | 587.46 | 1426.54 | 2014 |
Total | 614 | 1491 | 2105 |
Chi square=(fo-fe)^2/fe | |||
Yes | No | Total | |
Played games | 3.37 | 1.39 | 4.76 |
Never played games | 0.15 | 0.06 | 0.21 |
Total | 3.52 | 1.45 | 4.97 |
Test statistic:
Chi square=4.97
df=(2-1)*(2-1)=1
p-value=CHIDIST(4.97,1)=0.0258
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