a) find the probability that the last digit of the selected number is 6.
there are 10 possibility for last digit
hence probability = 1/10
B) find the probability that the last digit of the selected number is less than 3.
number which are less than 3 are 0,1, and 2
hence required probability = 3/10
C) determine the mean and standard deviation of the last digit
last digit can be 0,1,2,...9
hence mean = sum of all numbers / count of numbers
= 9/2
sd = ((b - a + 1)^2 - 1 )/12 , here a = 0 , b = 9
sd = (10^2 - 1)/12
= 99/12
= 33/4
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