Question

Suppose X has a normal distribution with mean 115 and variance 25. Find the 67th percentile of the distribution of X.

Answer #1

Given that the X has a normal distribution with mean = 115 and variance = 25, hence the standard deviation is . To find the 67th percentile of the distribution of X we need to find the Z score at 67th percentile which is calculated using the excel formula for normal distribution which is =NORM.S.INV(0.67), thus the Z is computed as 0.44

Now based on the Z -score formula the 67th percentile is computed as:

**Thus the 67th percentile of the distribution of X is
117.2**

Suppose X has a normal distribution with mean 115 and variance
25. Find the 67th percentile of the distribution of X.
Group of answer choices
117.2
136
134.8
131.425

Suppose X has a normal distribution with mean 115 and variance
25. Find the 67th percentile of the distribution of X.
A. 134.8
B. 117.2
C.136
D.131.425

Suppose X has a normal distribution with mean 120 and variance
36. Find the 67th percentile of the distribution of X.

Suppose that the random variable X follows a normal distribution
with mean 35 and variance 25.
a.) Calculate P(X > 37)
b.) Calculate P(32 < X < 38)
c.) Find the value of x so that P(X >x) is approximately
0.975

Suppose X has a normal distribution with mean 3 and standard
deviation 1. The 95th percentile of this distribution is
Group of answer choices
4.28
-4.28
4.94
-4.64
4.64
2.
Suppose X = 5 is a measurement from a normal population with
mean 2 and standard deviation 3. The corresponding Z-score is
Group of answer choices
2
5
0
1
3
3. Suppose X is a standard normal random variable. Among other
things this implies that the mean of X...

A) Suppose that X follows a normal distribution with a mean of
850 and a standard deviation of 100. Find P(X>700).
B) Suppose that X follows a normal distribution with a mean of
500 and a standard deviation of 100. For what sample size would you
expect a sample mean of 489 to be at the 33rd percentile?

Find the I.Q (Intelligence Quotient ) that is the 67th
percentile in a population of I.Q scores that is Normally
distributed with mean 110 and standard deviation 12:

A random variable X has this normal distribution: X ~ N(26,
12).
Find the 60th percentile.

X follows a normal distribution with mean=10 and sd=2,
find
a. the 30th percentile
b. P(9<X<12)

suppose y has a normal distribution with mean = 0 and variance =
1/theta. assume the prior distribution for theta is a gamma
distribution with parameters r and lambda.
a) what is the posterior distribution for theta?
b) find the squared error loss Bayes estimate for theta

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