Question

A balanced spinner wheel divided the whole surface into 6 equal pieces, and three pieces have number 2, two pieces have number 3 and one piece has number 4. 1) if we have two spinners wheels, what is the sample space and the probability of each outcome in the sample space.

2) what is the probability that the first spinner shows3 and the second spinner doesn't show 2 ?

3) Random variable X is defined as the sum of two spinner wheels. get the random variable of X ?

Answer 1

P(number 2) = 3/6 = 1/2

P(number 3) = 2/6 = 1/3

P(number 4) = 1/6

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a)

spinner one and two has numbers 2,3,4

sample space would be number on spinner 1 and spinner 2

sample space	P(X)	P(X)
22	1/2*1/2	0.25
23	1/2*1/3	0.166667
24	1/2*1/6	0.083333
32	1/3*1/2	0.166667
33	1/3*1/3	0.111111
34	1/3*1/6	0.055556
42	1/6*1/2	0.083333
43	1/6*1/3	0.055556
44	1/6*1/6	0.027778
	total	1

b)

P( first spinner shows3 and the second spinner doesn't show 2) = 1/3*1/2=0.1667

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c)

sample space			Sum
22			4
23			5
24			6
32			5
33			6
34			7
42			6
43			7
44			8

So, X is

X

4

5

6

7

8