Question

Suppose that 65 percent of a discount chain’s employees are women and 33 percent of the discount chain’s employees having a management position are women. If 25 percent of the discount chain’s employees have a management position...

A) what percentage of the discount chain’s female employees have management positions?

B) And is being a manager independent from being female?

Answer 1

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A.

p(women) = .65

p(mgmt pos has women) = .33

p(its mgmt pos) = .25

a. %ge of dc' female employees have mgmt pos = p(its mgmt pos)*p(mgmt pos has women)/p(women)

= .25*.33/.65

= .1269

B.

Mgmt pos Y N

women Y .33*65 .67*65

N 25-.33*65 75-.67*65

Total 25 75

b. p(mgmt) = .33

p(female) = .65

p(mgmt female) = .33*.65

Since p(mgmt )*P(female) = p(mgmt female) we conclude that being manager independent from being female)