Question

Every piece of M&M candy produced is supposed to weigh about 0.9 grams, with a standard deviation of about 0.03 grams. You wonder whether red M&Ms weigh more than the other colors, so you weigh a sample of 200 red M&Ms and discover their average weight is 0.902 grams. _____

(2pt) Part 1: What is the sample mean(x)? A.0.9 B.0.902 C.200 D.0.0

Part 2: What is the population mean(μ)? A.0.9 B.0.902 C.200 D.0.03

Part 3: Based on this information, what is the standard error of the mean(xs)? A.0.002    B.0.900    C.0.050    D.0.940_____ (2pts)

Part 4: Based on this information, which of the following value is closest to z? A.0.002     B.0.900     C.0.050      D.0.940_____ (2pts)

Part 4: Based on this information, what is the amount from the z-table? A.0.34134     B.0.31594    C.0.01995    D.0.32639_____ (4pts)

Part 5: Based on your research, is your sample of M&Ms significantly different than that of the population?    A.Yes     B. No

Answer 1

(2pt) Part 1: What is the sample mean(x(2pt)

average weight of all 200 candies

sample mean=0.902

ANSWER:0.902

Part 2: What is the population mean(μ)?

population mean=mu=0.9

ANSWER:0.9

Part 3: Based on this information, what is the standard error of the mean

std error=sigma/sqrt(n)

=0.03/sqr(200)

=0.00212132

=0.002

.002

Part 4: Based on this information, which of the following value is closest to z?

Z=xbar-mu/stderrror

=0.902-0.9/0.9428092

z=0.9428092

z=0.940

ANSWER:0.940

art 4: Based on this information, what is the amount from the z-table