Question

14 | 15 | 16 | 15 | |

Brown | 2 | 2 | 3 | 3 |

Yellow | 5 | 0 | 2 | 2 |

Red | 2 | 2 | 3 | 2 |

Orange | 2 | 1 | 1 | 0 |

Green | 1 | 5 | 2 | 2 |

Blue | 2 | 5 | 5 | 6 |

Using the data from your M&M’s, calculate the following confidence intervals with a 95% confidence,

a.) The proportion of Brown M&M’s in a bag.

b.) The proportion of Orange M&M’s in a bag.

c.) The proportion of Primary Colored (red, yellow, blue combined) M&M’s in a bag.

Answer #1

z score for 95% confidence interval is z = 1.96 (using z distribution table)

(A) Number of brown M&M's = 10

total number of M&M's = 14+15+16+15 = 60

proportion of brown M&M's = 10/60 = 0.167

Confidence interval =

this implies

(B) Number of brown M&M's = 4

total number of M&M's = 14+15+16+15 = 60

proportion of brown M&M's = 4/60 = 0.067

Confidence interval =

this implies

(C) Number of yellow, red and blue M&M's = 36

total number of M&M's = 14+15+16+15 = 60

proportion of yellow, red and blue M&M's = 36/60 = 0.6

Confidence interval =

this implies

Milk Chocolate M&M’s come in 6 colors; blue, orange, green,
yellow, red, and brown.
Choose the color of M&M’s you will be working with for this
project
Color:
GREEN
Using the collected data below from a single fun-sized bag,
provide the frequency and proportion of M&M’s in your color of
choice.
Red
Orange
Yellow
Green
Blue
Brown
2
1
2
3
5
1
Number of M&M's in your
color:
Total number of
M&M's:
Proportion of M&M's in
your color:
Construct...

According to a recent study, 21% of peanut M&M’s are brown,
5% are yellow, 16% are red, 11% are blue, 32% are orange, and 16%
are green. Assume these proportions are correct and suppose you
randomly select five peanut M&M’s from an extra-large bag of
the candies. Calculate the following probablities. Also calculate
the mean and standard deviation of the distribution. Round all
solutions to four decimal places, if necessary.
Compute the probability that exactly four of the five M&M’s...

According to Masterfoods, Inc., peanut M&M’s are 12% brown,
15% yellow, 12% red, 23% blue, 23% orange, and 15% green. On a
Saturday when you have run out of statistics homework, you decide
to test this claim. You purchase a medium bag of peanut M&M’s
and find 39 browns, 44 yellows, 36 red, 78 blue, 73 orange, and 48
greens. What type of hypothesis test should be used toTest
the hypothesis, do not solve.
Difference betweeen proprtions test (2prop-ztest)
Difference...

Mars Inc. claims that they produce M&Ms with the following
distributions:
Brown
30%
Red
20%
Yellow
20%
Orange
10%
Green
10%
Blue
10%
A bag of M&Ms was randomly selected from the grocery store
shelf, and the color counts were:
Brown
23
Red
23
Yellow
20
Orange
15
Green
17
Blue
15
Using the χ2 goodness of fit test to determine if the
proportion of M&Ms is what is claimed, what is the test
statistic?
a) χ2 = 10.409
b)...

A fun size bag of M&Ms has 4 blue, 3 orange, 3 red, 2
green, 2 yellow, and 1 brown M&Ms. What is the probability of
randomly selecting 5 M&Ms where 3 are blue and 2 are red?

2. According to Masterfoods, the company that manufactures
M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12%
are red, 23% are blue, 23% are orange and 15% are green. You
randomly select six peanut M&M’s from an extra-large bag of the
candies. (Round all probabilities below to four decimal places;
i.e. your answer should look like 0.1234, not 0.1234444 or 12.34%.)
a.) Compute the probability that exactly two of the six M&M’s
are yellow. b.) Compute the probability...

According to Masterfoods, the company that manufactures
M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12%
are red, 23% are blue, 23% are orange and 15% are green. (Round all
answers to 3 places after the decimal point, if necessary.) (a)
Compute the probability that a randomly selected peanut M&M is
not brown. P(not brown) = (b) Compute the probability that a
randomly selected peanut M&M is blue or red. P(blue or red) =
(c) Compute the probability...

Mars Inc. claims that they produce M&Ms with the following
distributions:
Brown
30%
Red
20%
Yellow
20%
Orange
10%
Green
10%
Blue
10%
A bag of M&Ms was randomly selected from the grocery store
shelf, and the color counts were:
Brown
25
Red
23
Yellow
21
Orange
13
Green
15
Blue
14
Using the χ2 goodness of fit test (α = 0.10) to
determine if the proportion of M&Ms is what is claimed. Select
the [p-value, Decision to Reject (RH0)...

According to Masterfoods, the company that manufactures
M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12%
are red, 23% are blue, 23% are orange and 15% are green.
Round your answers to three decimal places.
a) Compute the probability that a randomly selected peanut M&M
is not orange.
b) Compute the probability that a randomly selected peanut M&M
is yellow or orange.
c) Compute the probability that three randomly selected peanut
M&M’s are all blue.
d) If you...

According to Masterfoods, the company that manufactures
M&M’s, 12% of peanut M&M’s are brown, 15% are yellow, 12%
are red, 23% are blue, 23% are orange and 15% are green. You
randomly select six peanut M&M’s from an extra-large bag of the
candies. (Round all probabilities below to four decimal places;
i.e. your answer should look like 0.1234, not 0.1234444 or
12.34%.)
Compute the probability that exactly two of the six M&M’s
are brown.
Compute the probability that two or...

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 19 minutes ago

asked 47 minutes ago

asked 49 minutes ago

asked 56 minutes ago

asked 58 minutes ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 2 hours ago