Question

# 14 15 16 15 Brown 2 2 3 3 Yellow 5 0 2 2 Red 2...

 14 15 16 15 Brown 2 2 3 3 Yellow 5 0 2 2 Red 2 2 3 2 Orange 2 1 1 0 Green 1 5 2 2 Blue 2 5 5 6

Using the data from your M&M’s, calculate the following confidence intervals with a 95% confidence,

a.) The proportion of Brown M&M’s in a bag.

b.) The proportion of Orange M&M’s in a bag.

c.) The proportion of Primary Colored (red, yellow, blue combined) M&M’s in a bag.

z score for 95% confidence interval is z = 1.96 (using z distribution table)

(A) Number of brown M&M's = 10

total number of M&M's = 14+15+16+15 = 60

proportion of brown M&M's = 10/60 = 0.167

Confidence interval =

this implies

(B) Number of brown M&M's = 4

total number of M&M's = 14+15+16+15 = 60

proportion of brown M&M's = 4/60 = 0.067

Confidence interval =
this implies

(C) Number of yellow, red and blue M&M's = 36

total number of M&M's = 14+15+16+15 = 60

proportion of yellow, red and blue M&M's = 36/60 = 0.6
Confidence interval =
this implies

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