A big box store sells an average of 250 laptop computers per month , with a standard deviation of 100 laptops. suppose we take a sample for 10 months. Find the probability of that the sample mean mean number of laptops is greater than 275. The distribution of laptops is normal.
Solution:
We are given that: The distribution of laptops is normal with mean sells of 250 laptop computers per month, with a standard deviation of 100 laptops.
That is: and , n = number of months = 10
We have to find the probability that the sample mean number of laptops is greater than 275.
That is:
Thus find z score:
Thus we get:
Thus to P( Z < 0.79) , look in z table for z = 0.7 and 0.09 and find corresponding area.
For z = 0.7 and 0.09 , area is 0.7852
That is: P( Z< 0.79) = 0.7852
Thus
Thus, the probability that the sample mean number of laptops is greater than 275 is 0.2148.
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