Suppose that 500 parts are inspected for quality and 15 are rejected.
(a) Test the hypothesis H0: p = 0.02 against H1: p > 0.02 at α = 0.05.
(b) Find the p-value.
Solution :
This is the right tailed test .
The null and alternative hypothesis is
H0 : p = 0.02
Ha : p > 0.02
= x / n = 15 /500 = 0.03
P0 = 0.02
1 - P0 = 1 -0.02 = 0.98
Test statistic = z
= - P0 / [P0 * (1 - P0 ) / n]
=0.03 -0.02 / [0.02*(0.98) /500 ]
= 1.597
P(z > 1.597) = 1 - P(z < 1.597 ) = 0.0551
P-value = 0.0551
= 0.02
0.0551 < 0.02
Do not reject the null hypothesis .
There is insufficient evidence to suggest that
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