Part A: In a recent survey of 130 WMU graduates, 11 students said that parking was too limited on campus. What is the estimate of the population proportion? What is the standard error of this estimate?
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Part B: Suppose that in the United States the typical adult male is 67.98 inches tall with a standard deviation of 6.718. You take a random sample of 50 adult males. What is the probability that the mean height of the sample is less than 67.18?
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A) The estimate of the population proportion() = 11/130 = 0.0846
Standard error = sqrt((1  )/n)
= sqrt(0.0846 * (1  0.0846)/130)
= 0.0244
Option  2 is correct.
B) P( < 67.18)
= P((  )/() < (67.18  )/())
= P(Z < (67.18  67.98)/(6.718/))
= P(Z < 0.842)
= 0.2000
Option  5 is correct.
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