The Department of Labor would like to investigate if a difference exists in the proportion of men and women who are currently unemployed. A random sample of 150 men found that 15 were unemployed, and a random sample of 100 women found that 7 were unemployed. Perform a chi-square test for the Department of Labor using α = 0.01.
Following table shows the 2 by 2 table:
Unemployed | Employed | Total | |
Men | 15 | 135 | 150 |
Women | 7 | 93 | 100 |
Total | 22 | 228 | 250 |
Expected frequencies will be calculated as follows:
Following table shows the expected frequencies:
Unemployed | Employed | Total | |
Men | 13.2 | 136.8 | 150 |
Women | 8.8 | 91.2 | 100 |
Total | 22 | 228 | 250 |
Following table shows the calculations for chi square test statistics:
O | E | (O-E)^2/E |
15 | 13.2 | 0.245454545 |
7 | 8.8 | 0.368181818 |
135 | 136.8 | 0.023684211 |
93 | 91.2 | 0.035526316 |
Total | 0.67284689 |
The test statistics is:
Degree of freedom: df =( number of rows -1)*(number of columns-1) = (2-1)*(2-1)=1
The p-value is: 0.4121
Since p-value is greater than α = 0.01 so we cannot conclude that there is a difference exists in the proportion of men and women who are currently unemployed.
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