Noise levels at 4 volcanoes were measured in decibels yielding the following data: 153,156,168,138 Construct the 99% confidence interval for the mean noise level at such locations. Assume the population is approximately normal.
Step 1 of 4: Calculate the sample mean for the given sample data. Round your answer to one decimal place.
Step 2 of 4: Calculate the sample standard deviation for the given sample data. Round your answer to one decimal place.
Step 3 of 4: Find the critical value that should be used in constructing the confidence interval. Round your answer to three decimal places.
Step 4 of 4: Construct the 99% confidence interval. Round your answer to one decimal place.
1)
Sample mean = X / n
= 615 / 4
= 153.75
2)
Sample standard deviation = sqrt [ X2 - n 2 / n-1 ]
= sqrt [ 95013 - 4 * 153.752 / 3 ]
= 12.3390
3)
t critical value at 0.01 significance level with 3 df = 5.841
4)
99% confidence interval for is
- t * S / sqrt(n) < < + t * S / sqrt(n)
153.75 - 5.841 * 12.3390 / sqrt(4) < < 153.75 + 5.841 * 12.3390 / sqrt(4)
117.7 < < 189.7
99% CI is ( 117.7 , 189.7 )
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