Solution:
a) The number of female responses out of 10 responses is
modelled here as:
X ~ Bin(n = 10, p = 0.35)
The probability now is computed as:
P(X ≥ 2) = 1-[ P(X = 0) + P(X = 1 )]
= 1-[10C0 * 0.350*
0.6510 + 10C1 * 0.351 *
0.659]
= 1-[0.0135 + 0.0725]
= 0.9140
Therefore 0.9140 is the required probability here.
b) Probability that he will have 1 other male is computed here as:
= Total males / Total responses = 25/45 = 0.556
Therefore 0.556 is the required probability here.
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