With a mean of 100 and a standard deviation of 15, a random sample of 100 IQ scores is selected. The probability that the sample mean is less than k is 85%. Find k.
Given,
= 100 , = 15
Using central limit theorem,
P( < x) = P( Z < x - / / sqrt(n) )
We have to calculate k such that
P( X < k) = 0.85
P( Z < k - / / sqrt(n) ) = 0.85
From Z table, z-score for the probability of 0.85 is 1.0364
So,
k - / / sqrt(n) = 1.0364
k - 100 / (15 / sqrt(100) ) = 1.0364
Solve for k
k = 101.5546
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