1) A machine is designed to produce bolts with a 3-in diameter. The actual diameter of the bolts has a normal distribution with mean of 3.002 in and standard deviation of 0.002 in. Each bolt is measured and accepted if the length is within 0.005 in of 3 in; otherwise the bolt is scrapped. Find the percentage of bolts that are scrapped.
6.68% |
||
93.32% |
||
3.34% |
||
50% |
2)
A random variable X is normally distributed with a mean of 100. If P(X > 90) = 0.8413, then the standard deviation of X is
5 |
||
10 |
||
15 |
||
20 |
The systolic blood pressure of adults are approximately normally distributed with a mean of 128 and a standard deviation of 20. Give an interval in which the blood pressures of 68.26% of the population will fall.
88 to 168 |
||
68 to 188 |
||
108 to 148 |
||
88 to 188 |
(1)
μ = 3.002, σ = 0.002, x1 = 3 - 0.005 = 2.995, x2 = 3 + 0.005 = 3.005
z1 = (x - μ)/σ =(2.995 - 3.002)/0.002 = -3.5 and z2 = (x2 - μ)/σ = (3.005 - 3.002)/0.002 = 1.5
P(x < 2.995 or x > 3.005) = 0.067 (6.7%)
Answer: Option (a)
(2)
The right-tail z- score for 0.8413 is -1
(90 - 100)/σ = -1
Upon solving, we get σ = 10
Option (b)
(3)
68.26% corresponds to 1 standard deviation of the mean
x1 = 128 - 1 * 20 = 108, x2 = 128 + 1 * 20 = 148
The interval is [108, 148]
Option (c)
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