At 99% confidence, how large a sample should be taken to obtain a margin of error of 0.030 for the estimation of a population proportion? Assume that past data are not available for developing a planning value for p*. Round up to the next whole number.
Preliminary estimate for proportion (Not Known) = 0.5
Margin of error =E=0.03
Level of significance = 1-0.99=0.01
Z critical value is (by using Z table) =2.576
Sample size formula is
=1843.03
Therefore, sample size approximately will be 1844
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