A quality-conscious disk manufacturer wishes to know the fraction of disks his company makes which are defective. Step 2 of 2: Suppose a sample of 195 floppy disks is drawn. Of these disks, 11 were defective. Using the data, construct the 80% confidence interval for the population proportion of disks which are defective. Round your answers to three decimal places.
Sample proportion = 11 / 195
= 0.056
80% confidence interval for p is
- Z * sqrt
(
( 1 -
) / n) <
p <
+ Z * sqrt
(
( 1 -
) / n)
0.056 - 1.2816 * sqrt( 0.056 * 0.944 / 195) < p < 0.056 + 1.2816 * sqrt( 0.056 * 0.944 / 195)
0.035 < p < 0.077
80% CI is (0.035 , 0.077)
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