Question

# Construct a 99% confidence interval for mu 1 minus mu 2μ1−μ2 with the sample statistics for...

Construct a

99%

confidence interval for

mu 1 minus mu 2μ1−μ2

with the sample statistics for mean cholesterol content of a hamburger from two fast food chains and confidence interval construction formula below. Assume the populations are approximately normal with unequal variances.

 Stats ConfidenceConfidence interval wheninterval when variances arevariances are not equal x overbar 1 equals 134 mg comma s 1 equals 3.64 mg comma n 1 equals 20x1=134 mg, s1=3.64 mg, n1=20 x overbar 2 equals 88 mg comma s 2 equals 2.02 mg comma n 2 equals 16x2=88 mg, s2=2.02 mg, n2=16 left parenthesis x overbar 1 minus x overbar 2 right parenthesis minus t Subscript c Baseline StartRoot StartFraction s Subscript 1 Superscript 2 Over n 1 EndFraction plus StartFraction s Subscript 2 Superscript 2 Over n 2 EndFraction EndRoot less than mu 1 minus mu 2 less than left parenthesis x overbar 1 minus x overbar 2 right parenthesis plus t Subscript c Baseline StartRoot StartFraction s Subscript 1 Superscript 2 Over n 1 EndFraction plus StartFraction s Subscript 2 Superscript 2 Over n 2 EndFraction EndRootx1−x2−tcs21n1+s22n2<μ1−μ2

Enter the endpoints of the interval.

nothing less than mu 1 minus mu 2 less than nothing<μ1−μ2<

​(Round to the nearest integer as​ needed.)

Using Two sample t test assuming unequal variance.

Given: = 0.01

Population 1:

n1 = 20, = 134, S1 = 3.64

Population 2:

n2 = 16, = 88, S2 = 2.02

Degrees of Freedom:

Critical value:

…………………..….using t table

99% Confidence Interval:

(43.37, 48.63)

Or

43 < 1-2 < 49               .........rounded to the nearest integer

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