Question

1. Suppose you want to “prove” that the average hospital in the United States averages more than 700 births per year. Use the hospital database as your sample and test this hypothesis. Let alpha be 0.01. Make a hypothesis and alternative.

2. 	Qualitative Vs. Quantitative	Mean	Median	Mode	Range	Standard D.	Variance	CV	LOM
   Geo. Region	Qualitative	3.02	3	3	6	1.87	3.514	61.3392	Nominal
   Control	Qualitative	2.15	2	2	3	0.902	0.819	41.8120.937	Nominal
   Service	Qualitative	1.16	1	1	1	0.367	0.135	31.64	Nominal
   Census	Quantitative	144.095	104	28	1104	149.56	22435.16	103.33	Ratio
   Births	Quantitative	878.18	494	0	5699	1062.056	1133660	120.93	Ratio
   Personnel	Quantitative	865.30	596	328	4037	819.83	675518.2	94.744	Ratio

Answer 1

lets formulate the hypothesis first

h0 : average hospital in the United States averages is not more than 700 births per year
h1 : average hospital in the United States averages is more than 700 births per year

assuming alpha = 0.01 , if the p value of our test is less than 0.01 , then we reject the null hypothesis in favor of alternate hypothesis , otherwise not

now for births row from the table
m = 878.18
sd = 1062.056

we perform a z test here which is given by the formula

z = (x-mean)/sd

here x = 700

and we need to find P(X>700), please keep the z tables ready for this

z = (700-878.18)/1062.056 = -0.1677

P ( Z>−0.1677 )=P ( Z<0.1677 )=0.5675

The probability that Z>−0.1677 is equal to the blue area under the curve.

as the p value is not less than 0.01 , hence we fail to reject the null hypothesis and conclude that average hospital in the United States averages is not more than 700 births per year

Hope this helps . Please rate .