Three tables listed below show random variables and their probabilities. However, only one of these is actually a probability distribution.
A |
B |
C |
|||||
x |
P(x) |
x |
P(x) |
x |
P(x) |
||
25 |
0.1 |
25 |
0.1 |
25 |
0.1 |
||
50 |
0.3 |
50 |
0.3 |
50 |
0.3 |
||
75 |
0.4 |
75 |
0.4 |
75 |
0.4 |
||
100 |
0.2 |
100 |
0.4 |
100 |
0.6 |
a. Which of the above tables is a probability distribution?
(Click to select)BAC
b. Using the correct probability distribution, find the probability that x is: (Round the final answers to 1 decimal place.)
1. | Exactly 75 = | |
2. | No more than 50 = | |
3. | More than 25 = | |
c. Compute the mean, variance, and standard deviation of this distribution. (Round the final answers to 2 decimal places.)
1. | Mean µ | |
2. | Variance σ2 | |
3. | Standard deviation σ | |
a) To be a valid probability distribution, the sum of all proability must be equal to 1.
Sum for A = 0.1 + 0.3 + 0.4 + 0.2 = 1
Sum for B = 0.1 + 0.3 + 0.4 + 0.4 = 1.2
Sum for C = 0.1 + 0.3 + 0.4 + 0.6 = 1.4
So, Option-A) A is the correct answer.
b) P(exactly 75) = 0.4
P(no more than 50) = P(25) + P(50) = 0.1 + 0.3 = 0.4
P(more than 25) = 1 - P(25) = 1 - 0.1 = 0.9
c) Mean = E(X) = 25 * 0.1 + 50 * 0.3 + 75 * 0.4 + 100 * 0.2 = 67.5
E(X2) = 252 * 0.1 + 502 * 0.3 + 752 * 0.4 + 1002 * 0.2 = 5062.5
Variance = E(X2) - (E(X))2 = 5062.5 - 67.52 = 506.25
Standard deviation = sqrt(506.25) = 22.5
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