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Players A, B, and C toss a pair of fair dice in order (i,e., A, then...

Players A, B, and C toss a pair of fair dice in order (i,e., A, then B, then C, then A again, etc). The first player to get a sum 7 or 11 on their toss wins. What are their respective chances to win using product probabiliity on the sequence of tosses?

Math   Statistics-And-Probability   
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Solution: - Probability of getting a heads on a single toss = 1 / 2. A can win in following ways: Getting heads on first toss + not getting heads on first x nobody else gets heads on the first x get heads on second + … = 0.5333. B can win in following ways: (A does not get heads in first toss + B gets heads in first toss) + (Nobody get heads in first toss) x (A does not get heads in second toss) x B gets heads in second toss + ... = 0.2667. For C to win, we have: P(A and B do not get in their first toss)

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