Suppose that IQ scores have a bell-shaped distribution with a mean of 98 and a standard deviation of 17. Using the empirical rule, what percentage of IQ scores are greater than 115? Please do not round your answer.
Solution :
Given that,
= 98
= 17
Using Empirical rule,
P( - 1< X < + 1) = 68%
P(98 - 1 * 17 < X < 98 + 1 * 17) = 68%
P(81 < X < 115) = 68%
Here ,
P(X > 115) = 1 - P(X < 115) = 1 - 84% = 16%
Answer = 16%
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