Question

2.An experiment has been conducted for four treatments with eight blocks. Complete the following analysis of variance table

(to 2 decimals, if necessary and p-value to 4 decimals). If your answer is zero enter "0".

Source of Variation	Sum of Squares	Degrees of Freedom	Mean Square	F	p-value
Treatments	1,000
Blocks	600
Error
Total	1,900

Answer 1

Number of blocks(r)=8

number of treatments(k)= 4

the completed ANOVA table be:-

source of variation	sum of squares	degrees of freedom	mean square	F	p value
Treatments	1000	k-1= 4-1= 3	= 333.33	= 23.33	0.0000 [ for df1= 3,df2=21]
Blocks	600	r-1= 8-1= 7	= 85.71	= 6.00
Error	1900-(1000+600) = 300	(r-1)*(k-1)=(4-1)*(8-1) = 21	= 14.29
Total	1900	3+7+21= 31

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