2.An experiment has been conducted for four treatments with eight blocks. Complete the following analysis of variance table
(to 2 decimals, if necessary and pvalue to 4 decimals). If your answer is zero enter "0".
Source of Variation  Sum of Squares  Degrees of Freedom  Mean Square  F  pvalue  
Treatments  1,000  
Blocks  600  
Error  
Total  1,900 
Number of blocks(r)=8
number of treatments(k)= 4
the completed ANOVA table be:
source of variation  sum of squares  degrees of freedom  mean square  F  p value 
Treatments  1000  k1= 41= 3  = 333.33 
= 23.33 
0.0000 [ for df1= 3,df2=21] 
Blocks  600  r1= 81= 7  = 85.71 
= 6.00 

Error 
1900(1000+600) = 300 
(r1)*(k1)=(41)*(81) = 21 
= 14.29  
Total  1900  3+7+21= 31 
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