For normally distributed data with μ = 100, and σ = 10, what value of x in the right tail has 0.40 area between the mean and x?
P(X < A) = P(Z < (A - )/)
= 100
= 10
Area between mean and x in the right tail = 0.40
That is P(100 < X < x) = 0.40
P(X < x) = 0.5 + 0.4 = 0.90
P(Z < (x - 100)/10) = 0.90
Take the value of z corresponding to 0.90 from standard normal distribution table.
(x - 100)/10 = 1.28
x = 1.28 x 10 + 100
x = 112.8
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