Repeated data on individuals who participated in a randomized experiment are presented below.
Participants |
1 |
2 |
3 |
4 |
5 |
6 |
7 |
8 |
Assessment I |
160 |
180 |
200 |
190 |
210 |
180 |
210 |
190 |
Assessment II |
200 |
230 |
210 |
235 |
240 |
195 |
230 |
200 |
Is the mean difference from this experiment statistically significant? Assume the level of significance is 5%. Use the steps for hypothesis testing and show all your work.
Here, we have to use paired t test.
The null and alternative hypotheses for this test are given as below:
H0: µd = 0 versus Ha: µd ≠ 0
This is a two tailed test.
Test statistic for paired t test is given as below:
t = (Dbar - µd)/[Sd/sqrt(n)]
From given data, we have
µd =0
Dbar = -27.5
Sd = 16.0357
n = 8
df = n – 1 = 7
α = 0.05
t = (Dbar - µd)/[Sd/sqrt(n)]
t = (-27.5 - 0)/[ 16.0357/sqrt(8)]
t = -4.8505
The p-value by using t-table is given as below:
P-value = 0.0019
P-value < α = 0.05
So, we reject the null hypothesis
There is sufficient evidence to conclude that the mean difference is statistically significant at 5% level.
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