Question

We wish to estimate what percent of adult residents in a certain county are parents. Out of 500 adult residents sampled, 360 had kids. Based on this, construct a 90% confidence interval for the proportion p of adult residents who are parents in this county. Give your answers as decimals, to 4 places. Answer = ± (Note this is NOT in interval form, so check your answer carefull

Answer #1

Hello

Here we have given that,

x = number of kids = 360

n = total number of residents = 500

We have to find 90% confidence interval for the proportion p of adult residents who are parents in this country.

90% confidence interval for the proportion p of adult residents who are parents in this county is,

- E < P < + E

where is sample proportion.

= x/n = 360 / 500 = 0.72

E is margin of error.

lower limit = - E = 0.72 - 0.033 = 0.687

upper limit = + E = 0.72 + 0.033 = 0.753

90% confidence interval for the proportion p of adult residents who are parents in this county is (0.687,0.753).

I hope this solves your query.

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