Question

The pH factor is a measure of the acidity or alkalinity of water. A reading of...

The pH factor is a measure of the acidity or alkalinity of water. A reading of 7.0 is neutral; values in excess of 7.0 indicate alkalinity; those below 7.0 imply acidity. Loren Hill states that the best chance of catching bass occurs when the pH of the water is in the range 7.5 to 7.9. Suppose you suspect that acid rain is lowering the pH of your favorite fishing spot and you wish to determine whether the pH is less than 7.5.

(a) State the alternative and null hypotheses that you would choose for a statistical test. (Choose Correct Letter)

a) H0: μ < 7.5 versus Ha: μ > 7.5

b) H0: μ = 7.5 versus Ha: μ > 7.5

c) H0: μ ≠ 7.5 versus Ha: μ = 7.5

d) H0: μ = 7.5 versus Ha: μ ≠ 7.5

e) H0: μ = 7.5 versus Ha: μ < 7.5


(b) Does the alternative hypothesis in part (a) imply a one- or a two-tailed test? Explain. (Choose Correct Letter)

a) Since it is necessary to test that the average pH level is less than 7.5, the test is one-tailed.

b) Since it is necessary to test that the average pH level is more than 7.5, the test is one-tailed.    

c) Since it is necessary to test that the average pH level is different from 7.5, the test is two-tailed.

d) Since it is necessary to test that the average pH level is less than 7.5, the test is two-tailed.

e) Since it is necessary to test that the average pH level is different from 7.5, the test is one-tailed.


(c) Suppose that a random sample of 20 water specimens gave pH readings with x = 7.4 and s = 0.1. Just glancing at the data, do you think that the difference

x − 7.5 = −0.1 is large enough to indicate that the mean pH of the water samples is less than 7.5? (Do not conduct the test.)

Homework Answers

Answer #1

(a) The given claim : The pH is less than 7.5 is represents the alternative hypothesis Ha.

Under H0 we assume the equality.

Therefore null and alternative hypothesis would be,

e) H0: μ = 7.5 versus Ha: μ < 7.5

(b) Since the alternative hypothesis consists of less than "<" sign , this is one left tail test.

a) Since it is necessary to test that the average pH level is less than 7.5, the test is one-tailed.

(c) Since n = 20 , it is small sample test and sample standard deviation s = 0.1 which is fairly smaller.

So the standard error of the sample mean would be enough smaller ,we are aslo given x bar = 7.4 which makes the test statistic larger and it results into significant evidence that mean pH of the water sample is less than 7.5

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
Acid rain—rain with a pH value less than 5.7, caused by the reaction of certain air...
Acid rain—rain with a pH value less than 5.7, caused by the reaction of certain air pollutants with rainwater—is a growing problem in the United States. Pure rain falling through clean air registers a pH value of 5.7 (pH is a measure of acidity: 0 is acid; 14 is alkaline). A sample of n = 30 rainfalls produced pH readings with x = 3.7 and s = 0.5. Do the data provide sufficient evidence to indicate that the mean pH...
Most water-treatment facilities monitor the quality of their drinking water on an hourly basis. One variable...
Most water-treatment facilities monitor the quality of their drinking water on an hourly basis. One variable monitored is pH, which measures the degree of alkalinity or acidity in the water. A pH below 7.0 is acidic, one above 7.0 is alkaline, and a pH of 7.0 is neutral. One water-treatment plant has a target pH of 8.5. 11 water samples are drawn at this plant. The plant wants to know if the median pH level in the water differs from...
Let x be a random variable that represents the pH of arterial plasma (i.e., acidity of...
Let x be a random variable that represents the pH of arterial plasma (i.e., acidity of the blood). For healthy adults, the mean of the x distribution is typically 7.4 (Reference: Merck Manual, a commonly used reference in medical schools and nursing programs). A new drug for arthritis has been developed. However, it is thought that this drug may change blood pH. A random sample of 33 patients with arthritis took the drug for 3 months. Blood tests showed that...
Let x be a random variable that represents the pH of arterial plasma (i.e., acidity of...
Let x be a random variable that represents the pH of arterial plasma (i.e., acidity of the blood). For healthy adults, the mean of the x distribution is μ = 7.4.† A new drug for arthritis has been developed. However, it is thought that this drug may change blood pH. A random sample of 41 patients with arthritis took the drug for 3 months. Blood tests showed that x = 8.6 with sample standard deviation s = 3.2. Use a...
To properly treat patients, drugs prescribed by physicians must not only have a mean potency value...
To properly treat patients, drugs prescribed by physicians must not only have a mean potency value as specified on the drug's container, but also the variation in potency values must be small. Otherwise, pharmacists would be distributing drug prescriptions that could be harmfully potent or have a low potency and be ineffective. A drug manufacturer claims that his drug has a potency of 5 ± 0.1 milligram per cubic centimeter (mg/cc). A random sample of four containers gave potency readings...
Industrial wastes and sewage dumped into our rivers and streams absorb oxygen and thereby reduce the...
Industrial wastes and sewage dumped into our rivers and streams absorb oxygen and thereby reduce the amount of dissolved oxygen available for fish and other forms of aquatic life. One state agency requires a minimum of 5 parts per million (ppm) of dissolved oxygen in order for the oxygen content to be sufficient to support aquatic life. Six water specimens taken from a river at a specific location during the low-water season (July) gave readings of 4.9, 5.0, 5.0, 5.1,...
Let x be a random variable that represents the pH of arterial plasma (i.e., acidity of...
Let x be a random variable that represents the pH of arterial plasma (i.e., acidity of the blood). For healthy adults, the mean of the x distribution is μ = 7.4.† A new drug for arthritis has been developed. However, it is thought that this drug may change blood pH. A random sample of 31 patients with arthritis took the drug for 3 months. Blood tests showed that x = 8.5 with sample standard deviation s = 2.5. Use a...
Let x be a random variable that represents the pH of arterial plasma (i.e., acidity of...
Let x be a random variable that represents the pH of arterial plasma (i.e., acidity of the blood). For healthy adults, the mean of the x distribution is μ = 7.4.† A new drug for arthritis has been developed. However, it is thought that this drug may change blood pH. A random sample of 41 patients with arthritis took the drug for 3 months. Blood tests showed that x = 8.6 with sample standard deviation s = 3.0. Use a...
Let x be a random variable that represents the pH of arterial plasma (i.e., acidity of...
Let x be a random variable that represents the pH of arterial plasma (i.e., acidity of the blood). For healthy adults, the mean of the x distribution is μ = 7.4.† A new drug for arthritis has been developed. However, it is thought that this drug may change blood pH. A random sample of 36 patients with arthritis took the drug for 3 months. Blood tests showed that x = 8.6 with sample standard deviation s = 3.2. Use a...
Let x be a random variable that represents the pH of arterial plasma (i.e., acidity of...
Let x be a random variable that represents the pH of arterial plasma (i.e., acidity of the blood). For healthy adults, the mean of the x distribution is μ = 7.4.† A new drug for arthritis has been developed. However, it is thought that this drug may change blood pH. A random sample of 31 patients with arthritis took the drug for 3 months. Blood tests showed that x = 8.8 with sample standard deviation s = 3.0. Use a...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT