Question

Let z denote a standard normal random variable.

a. Find P(z > 1.48).

b. Find P(-0.44 < z < 2.68).

c. Determine the value of which

satisfies P(z > z. ) = 0.7995. d. Find P(z <
–0.87).

Answer #1

Part a)

P ( Z > 1.48 ) = 1 - P ( Z < 1.48 ) = 1 - 0.9306 =
0.0694

Part b)

P ( -0.44 < Z < 2.68 ) = P ( Z < 2.68 ) - P ( Z <
-0.44 ) = 0.9963 - 0.33 = 0.6664

Part c)

P ( Z > ? ) = 0.7995

P ( Z > ? ) = 1 - P ( Z < ? ) = 1 - 0.7995 = 0.2005

Looking for probability 0.2005 in standard normal table to find the critical value

Z = - 0.84

P ( Z > -0.84 ) = 0.7995

Part d)

P( Z < –0.87 )

Z = -0.87 = P ( Z < -0.87 ) = 0.1922

Looking for critical value z = -0.87 in standard normal table to find the probability.

Let Z denote the standard normal random variable. If P( 1 < Z
< c ) = 0.128, what is the value of
c ?

Let "Z" be a random variable from the standard normal
distribution. Find the value for ? that satisfies each of
the following probabilities.
(Round all answers to two decimal places)
A) P(Z < ?) = 0.6829.
? =
B) P(Z > ?) = 0.3087.
? =
C) P(-? < Z < ?) =
0.7402.
? = ±

Let z denote the standard normal random variable. Find the value
of z0z0 such that:
(a) P(z≤z0)=0.89P(z≤z0)=0.89
z0=z0=
(b) P(−z0≤z≤z0)=0.039P(−z0≤z≤z0)=0.039
z0=z0=
(c) P(−z0≤z≤z0)=0.1112P(−z0≤z≤z0)=0.1112
z0=z0=
(d) P(z≥z0)=0.0497P(z≥z0)=0.0497
z0=z0=
(e) P(−z0≤z≤0)=0.4874P(−z0≤z≤0)=0.4874
z0=z0=
(f) P(−2.03≤z≤z0)=0.5540P(−2.03≤z≤z0)=0.5540
z0=z0=

Let z denote a variable that has a standard normal
distribution. Determine the value z* to satisfy the
following conditions. (Round all answers to two decimal
places.)
(a) P(z < z*) = 0.0256
z* =
(b) P(z < z*) = 0.0097
z* =
(c) P(z < z*) = 0.0484
z* =
(d) P(z > z*) = 0.0204
z* =
(e) P(z > z*) = 0.0097
z* =
(f) P(z > z* or z <
−z*) = 0.2007
z* =

A: Let z be a random variable with a standard normal
distribution. Find the indicated probability. (Round your answer to
four decimal places.)
P(z ≤ 1.11) =
B: Let z be a random variable with a standard normal
distribution. Find the indicated probability. (Round your answer to
four decimal places.)
P(z ≥ −1.24) =
C: Let z be a random variable with a standard normal
distribution. Find the indicated probability. (Round your answer to
four decimal places.)
P(−1.78 ≤ z...

Let Z be the standard normal variable. Find the values of z if z
satisfies the given probabilities. (Round your answers to two
decimal places.) (a) P(Z > z) = 0.9678 z =
(b) P(−z < Z < z) = 0.7888 z =

let z be a standard normal random variable. find z1 such that
p(-2.3<z<z1)= 0.1046

Find the probabilities associated with the standard normal
random variable Z:
a) P (Z> 2.54)
b) P (-3.2 <Z <3.2)
c) P (Z <1.94)
d) P (Z> 2.88)
e) P (Z> 3.15)

Let z denote a random variable having a normal distribution with
μ = 0 and σ = 1. Determine each of the probabilities below. (Round
all answers to four decimal places.) (a) P(z < 0.1) = (b) P(z
< -0.1) = (c) P(0.40 < z < 0.84) = (d) P(-0.84 < z <
-0.40) = (e) P(-0.40 < z < 0.84) = (f) P(z > -1.25) = (g)
P(z < -1.51 or z > 2.50) =

Let z denote a random variable having a normal
distribution with μ = 0 and σ = 1. Determine each
of the probabilities below. (Round all answers to four decimal
places.)
(a) P(z < 0.1) =
(b) P(z < -0.1) =
(c) P(0.40 < z < 0.85) =
(d) P(-0.85 < z < -0.40)
=
(e) P(-0.40 < z < 0.85) =
(f) P(z > -1.26) =
(g) P(z < -1.49 or z > 2.50) =

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 2 minutes ago

asked 8 minutes ago

asked 9 minutes ago

asked 32 minutes ago

asked 37 minutes ago

asked 45 minutes ago

asked 48 minutes ago

asked 54 minutes ago

asked 57 minutes ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago