Question

1) A researcher reports that when groups of four children are randomly selected from a population of couples meeting certain criteria, the probability distribution for the number of girls, ?, is given in the following table where ? is a positive constant.

x |
?(?) |
?(? ≤ ?) |

0 |
0.4 |
? |

1 |
? |
? |

2 |
3? − 0.2 |
? |

3 |
2? |
? |

4 |
0.2 |
? |

a) Find ?(2).

b) Complete the column of cumulative probability. (Please rewrite
the table in your answer sheet) c)What is the probability of
getting at least one girl?

d) What is the probability of getting more than one and less than
three girls?

e) What is the probability of getting at most three girls?

f) What are the mean, the variance and the standard deviation of
??

7) The lengths of pregnancies are normally distributed with a mean of 250 days and a standard deviation of 10 days.

a) Find the probability of a pregnancy lasting less than 270 days.

b) If we stipulate that a baby is premature if the length of pregnancy is the lowest 3%, find the length that separates premature babies from those who are not premature.

8) The response time of a fire department in an emergency call is the period between the time the call is received by the dispatcher and the time the first truck service arrives on the scene. It was found that the response time follows a normal distribution with mean of 10 min and standard deviation of 3 min. What is the probability that the response time is exactly equal to 17.5 min?

Answer #1

dear student lease post the question one at a time.

7) For the probability distribution to be valid.

.......(1)

Hence .......(2)

Using 1 and 2

now

a)P(2) = 3k-0.2=3(0.1)-0.2=0.1

b)

x | p(x) | |

0 | 0.4 | 0.4 |

1 | 0.1 | 0.5 |

2 | 0.1 | 0.6 |

3 | 0.2 | 0.8 |

4 | 0.2 | 1 |

c) The probability of getting at least one girl is

d) the probability of getting more than one and less than three girls = Probability of getting 2 girls = 0.1

e) the probability of getting at most three girls =

f) Mean =

standard deviation =

The lengths of pregnancies are normally distributed with a mean
of 266 days and a standard deviation of 15 days. a. Find the
probability of a pregnancy lasting 309 days or longer. b. If the
length of pregnancy is in the lowest 4 %, then the baby is
premature. Find the length that separates premature babies from
those who are not premature.

The lengths of pregnancies are normally distributed with a mean
of 266 days and a standard deviation of 15 days. a) Find the
probability of a pregnancy lasting 307 days or longer. b) If the
length of pregnancy is in the lowest 44%, then the baby is
premature. Find the length that separates premature babies from
those who are not premature.

The lengths of pregnancies are normally distributed with a mean
of 270 days and a standard deviation of 15 days. a. Find the
probability of a pregnancy lasting 309 days or longer. b. If the
length of pregnancy is in the lowest 22%, then the baby is
premature. Find the length that separates premature babies from
those who are not premature.

The lengths of pregnancies are normally distributed with a mean
of 268 days and a standard deviation of 15 days. a. Find the
probability of a pregnancy lasting 308 days or longer. b. If the
length of pregnancy is in the lowest 3%, then the baby is
premature. Find the length that separates premature babies from
those who are not premature.
a. The probability that a pregnancy will last 308 days or longer
is ?
b. Babies who are born...

The lengths of pregnancies are normally distributed with a mean
of 267 days and a standard deviation of 15 days. a. Find the
probability of a pregnancy lasting 309days or longer. b. If the
length of pregnancy is in the lowest 33%, then the baby is
premature. Find the length that separates premature babies from
those who are not premature.
The probability that a pregnancy will last
309 days or longer is nothing

The lengths of pregnancies are normally distributed with a mean
of 266 days and a standard deviation of 15 days. a. Find the
probability of a pregnancy lasting 308 days or longer. b. If the
length of pregnancy is in the lowest 3 %, then the baby is
premature. Find the length that separates premature babies from
those who are not premature. Click to view page 1 of the table.
LOADING... Click to view page 2 of the table. LOADING......

The lengths of pregnancies are normally distributed with a mean
of 266 days and a standard deviation of 15 days. a. Find the
probability of a pregnancy lasting 307 days or longer. b. If the
length of pregnancy is in the lowest 44%,then the baby is
premature. Find the length that separates premature babies from
those who are not premature.
a. The probability that a pregnancy will last 307 days or longer
is [ ]. (Round to four decimal places)...

he lengths of pregnancies are normally distributed with a mean
of
267
days and a standard deviation of
1515
days. a. Find the probability of a pregnancy lasting
309309
days or longer. b. If the length of pregnancy is in the
lowest
3 percent
then the baby is premature. Find the length that separates
premature babies from those who are not premature.Click to view
page 1 of the table.
LOADING...
Click to view page 2 of the table.
LOADING...
a....

The lengths of pregnancies are normally distributed with a mean
of
267267
days and a standard deviation of
1515
days. a. Find the probability of a pregnancy lasting
308308
days or longer. b. If the length of pregnancy is in the
lowest
22%,
then the baby is premature. Find the length that separates
premature babies from those who are not premature.Click to view
page 1 of the table.
LOADING...
Click to view page 2 of the table.
LOADING...
a. The...

The lengths of pregnancies are normally distributed with a mean
of
270270
days and a standard deviation of
1515
days. a. Find the probability of a pregnancy lasting
309309
days or longer. b. If the length of pregnancy is in the
lowest
33%,
then the baby is premature. Find the length that separates
premature babies from those who are not premature.Click to view
page 1 of the table.
LOADING...
Click to view page 2 of the table.
LOADING...
a. The...

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