Question

A simple random sample of 44 adults is obtained from a normally distributed? population, and each? person's red blood cell count? (in cells per? microliter) is measured. The sample mean is 5.23 and the sample standard deviation is 0.53. Use a 0.05 significance level and the given calculator display to test the claim that the sample is from a population with a mean less than 5.4 comma which is a value often used for the upper limit of the range of normal values. What do the results suggest about the sample? group? ? T-Test ??muless than5.4 ??tequalsnegative 2.127646092 ??pequals0.0195702251 ??x overbarequals5.23 ??Sxequals0.53 ??nequals44 What are the null and alternative? hypotheses? A. Upper H 0?: muequals5.4 Upper H 1?: mugreater than5.4 B. Upper H 0?: muequals5.4 Upper H 1?: munot equals5.4 C. Upper H 0?: muless than5.4 Upper H 1?: muequals5.4 D. Upper H 0?: muequals5.4 Upper H 1?: muless than5.4 identify the test statistic? identify the p value? state the final conclusion? what do the results suggest?

Answer 1

Here claim is that mean is less than 5.4

So hypothesis is vs

Now here it is given that and s=0.53

As n=44>30, we will use z test statistics

As alternative hypothesis is having less than value, it is left tailed test

So P value is

As P value is less than 0.05 significance level, we reject the null hypothesis

Hence we have sufficient evidence to support the claim that mean is less than 5.4