Question

For these questions, please use the “traditional method” that we covered in class (and appears on...

For these questions, please use the “traditional method” that we covered in class (and appears on page 341 in the text). In a simple random sample of 70 automobiles registered in a certain state, 28 of them were found to have emission levels that exceed a state standard.

1.How many automobiles must be sampled to specify the proportion that exceed the standard to within ±0.10 with 95% confidence? Use your estimate from Question 1 for p. Round your answer up to the nearest whole number.

2.How many automobiles must be sampled to specify the proportion that exceed the standard to within ±0.10 with 98% confidence? Use your estimate from Question 1 for p. Round your answer up to the nearest whole number.

Homework Answers

Answer #1

1)

here margin of error E = 0.100
for95% CI crtiical Z          = 1.960
estimated proportion=p= 0.400
required sample size n =         p*(1-p)*(z/E)2= 93.00

2)

here margin of error E = 0.100
for98% CI crtiical Z          = 2.33
estimated proportion=p= 0.400
required sample size n =         p*(1-p)*(z/E)2= 131.00

(try 130 if z value is not rounded to 2 places)

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
In a simple random sample of 70 automobiles registered in a certain state, 24 of them...
In a simple random sample of 70 automobiles registered in a certain state, 24 of them were found to have emission levels that exceed a state standard. What proportion of the automobiles in the sample had emission levels that exceed the standard? Round the answer to two decimal places. Find a 95% confidence interval for the proportion of automobiles in the state whose emission levels exceed the standard. Round the answers to three decimal places. Find a 98% confidence interval...
A sample of 75 concrete blocks had a mean mass of 38.3 kg with a standard...
A sample of 75 concrete blocks had a mean mass of 38.3 kg with a standard deviation of 0.5 kg. How many blocks must be sampled so that a 99% confidence interval will specify the mean mass to within ±0.1 kg? (Round up the final answer to the nearest integer.) The number of blocks that must be sampled is
Use Excel please.( norm.inv, t.inv, ) QUESTION 2 (a) Suppose that your task is to estimate...
Use Excel please.( norm.inv, t.inv, ) QUESTION 2 (a) Suppose that your task is to estimate the mean of a normally distributed population to within 8 units with 95% confidence and that the population standard deviation is known to be 72. What sample size should be used if you wish to estimate the population mean to within 8 units? (b) Determine the minimum sample size required for estimating the population proportion of number of people who drive to work, to...
For this problem, carry at least four digits after the decimal in your calculations. Answers may...
For this problem, carry at least four digits after the decimal in your calculations. Answers may vary slightly due to rounding. The National Council of Small Businesses is interested in the proportion of small businesses that declared Chapter 11 bankruptcy last year. Since there are so many small businesses, the National Council intends to estimate the proportion from a random sample. Let p be the proportion of small businesses that declared Chapter 11 bankruptcy last year. (a) If no preliminary...
In the planning stage, a sample proportion is estimated as pˆp^ = 54/60 = 0.90. Use...
In the planning stage, a sample proportion is estimated as pˆp^ = 54/60 = 0.90. Use this information to compute the minimum sample size n required to estimate p with 95% confidence if the desired margin of error E = 0.09. What happens to n if you decide to estimate p with 90% confidence? Use Table 1. (Round intermediate calculations to 4 decimal places and "z-value" to 3 decimal places. Round up your answers to the nearest whole number.)   ...
The population standard deviation for the height of college basketball players is 2.9 inches. If we...
The population standard deviation for the height of college basketball players is 2.9 inches. If we want to estimate 92% confidence interval for the population mean height of these players with a 0.6 margin of error, how many randomly selected players must be surveyed? (Round up your answer to nearest whole number)
The population standard deviation for the height of college basketball players is 3.1 inches. If we...
The population standard deviation for the height of college basketball players is 3.1 inches. If we want to estimate 99% confidence interval for the population mean height of these players with a 0.58 margin of error, how many randomly selected players must be surveyed? (Round up your answer to nearest whole number)
The population standard deviation for the height of college basketball players is 3 inches. If we...
The population standard deviation for the height of college basketball players is 3 inches. If we want to estimate 99% confidence interval for the population mean height of these players with a 0.7 margin of error, how many randomly selected players must be surveyed?  (Round up your answer to nearest whole number)
The population standard deviation for the height of college baseball players is 3.2 inches. If we...
The population standard deviation for the height of college baseball players is 3.2 inches. If we want to estimate 90% confidence interval for the population mean height of these players with a 0.7 margin of error, how many randomly selected players must be surveyed? (Round up your answer to nearest whole number)
The population standard deviation for the height of college football players is 3.3 inches. If we...
The population standard deviation for the height of college football players is 3.3 inches. If we want to estimate a 90% confidence interval for the population mean height of these players with a 0.7 margin of error, how many randomly selected players must be surveyed? (Round up your answer to nearest whole number) Answer: