You pick two orange balls and two green balls from a bag. You then randomly scramble them and put them in a line. What is the probability that orange and green balls won't mix (e.g. two organ balls followed by two green balls or the other way around)?
Number of ways in which 4 balls can be arranged = 4!
But if some are identical, we need to divide 4! by factorial of number of identical balls
Number of ways in which 2 orange balls are 2 green balls can be arranged = 4!/(2!x2!) = 6
Number of ways in which balls can be arranged such that two oranges are together and 2 greens are together = 2!
= 2 (OOGG, GGOO)
P(orange and green balls won't mix) = Number of ways in which balls can be arranged such that two oranges are together and 2 greens are together / Number of ways in which 2 orange balls are 2 green balls can be arranged
= 2/6
= 1/3
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