1. Assume that you are interested in the likelihood that a stream violates water quality regulations. Assume 15% of streams are impaired. Also assume that that there is a 90% chance of detecting an impaired stream if it really is impaired (10% chance it will not be detected). Also assume that 5% of streams that are healthy are erroneously tested as impaired.
Fill-in the decision table with following conditional probabilities.
Dectected | Missed | ||
Healthy | |||
Impaired | |||
a. What is the probability that a stream will be detected as impaired?
b. Calculate the probability that a stream is impaired if a test comes back positive? Show your work
c. Calculate the probability that a stream is actually healthy if a test comes back negative? Show your work
Let H and I be the events that the stream is healthy and impaired respectively.
Also, let D and N be the events that impairment is detected and not detected respectively.
Since given that 15% stream are impaired.
P(I) = 0.15
Probability that a stream is healthy =P(H) = 1-P(I) = 1-0.15 = 0.85
Probability of defecting an impaired stream if it is impaired = P(D|I) = 0.90
Probability of not detecting an impaired stream given it is impaired = P(N|I) = 0.10
Probability that it is healthy and detected as impaired = P(HI) = 0.05
So,
So,
So the decision table will be :
Detected | missed (not detected) | total | |
---|---|---|---|
Healthy | 0.05 | 0.80 | 0.85 |
Impaired | 0.135 | 0.015 | 0.15 |
Total | 0.185 | 0.815 | 1 |
Thus,
Probability that the stream will be detected as impaired = P(D) = 0.185
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